A) 41
B) 23
C) 14
D) 32
Correct Answer: D
Solution :
Let left and right digit be x and y respectively. Then the number will be \[f(x)=ax+b\] According to the question, \[f(x)=a{{x}^{2}}+bx+c\ne 0\] ?(1) \[(x+1)\times 8=10x+y\] \[p(x)=3{{x}^{2}}{{y}^{3}}+5x{{y}^{7}}-{{x}^{6}}\] \[2x+y=8\] ...(2) Solving equations (1) and (2), we have \[{{x}^{3}}+{{x}^{2}}-4x+8\] Hence, the required numbers is 32.You need to login to perform this action.
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