A) \[a{{x}^{2}}+bx+c=0\]
B) \[a\ne 0\]
C) \[4{{x}^{2}}-4x-3=0\]
D) none of these
Correct Answer: B
Solution :
\[0<a<1\] \[=({{x}^{2}}\times {{x}^{2}})+(3x+{{x}^{2}})+(5\times {{x}^{2}})+[{{x}^{2}}\times (-1)]+[3x\times (-1)]+[5(-1)]\] \[x+y=6\]
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