A) \[4{{x}^{2}}+3x=0,5{{x}^{2}}\]
B) \[a{{x}^{2}}+bx+c=0\]
C) \[a{{\alpha }^{2}}+b\alpha +c=0\]
D) \[5{{x}^{2}}-7x-6=0.\]
Correct Answer: A
Solution :
\[\underline{\underset{\underset{{}}{\mathop{{{x}^{4}}\,-\,{{x}^{3}}+{{x}^{2}}\,-\,\,4\,x\,\,+\,\,8}}\,}{\mathop{\underline{\begin{align} & {{x}^{4}}+0+2{{x}^{2}}-3x+7 \\ & (-)\,\,\,\,\,\,\,\,{{x}^{3}}+{{x}^{2}}+x-1 \\ \end{align}}}}\,}\]
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