A) \[x=-2\]
B) \[(x-y)(x+2z)\]
C) \[(x+y)(x-2z)\]
D) \[(x-y)(x-2z)\]
Correct Answer: B
Solution :
Given \[{{x}^{2}}-x-6=0\] \[\Rightarrow \] \[y=-1\] \[\Rightarrow \] \[xy=-1\] \[\Rightarrow \] \[{{(a+b)}^{3}}-{{(a-b)}^{3}}=\_\_\_\_\_.\] \[{{b}^{3}}+3{{a}^{2}}b\] \[x-3=0\] or \[x+2=0\] \[\Rightarrow \] \[x=3\] or \[x=-2\] \[x+y=6\] Solution set is\[3x-y=4,\].
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