A) 11
B) 21
C) 10
D) 12
Correct Answer: D
Solution :
We have, \[pqa={{(3p+q)}^{2}}-{{(3p-q)}^{2}}\] \[=(3p+q+3p-q)(3p+q-3p+q)\] \[\text{ }\!\![\!\!\text{ Using }{{x}^{2}}-{{y}^{2}}=(x+y)(x-y)]\] \[=6p\times 2q\] \[\Rightarrow pqa=12pq\] \[\therefore a=\frac{12pq}{pq}=12\]You need to login to perform this action.
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