A) \[\text{(10a+20b) units}\]
B) \[\text{(4a+30) units}\]
C) \[\text{(2a + 2b) units}\]
D) \[\text{(8a + 60) units}\]
Correct Answer: D
Solution :
Area of rectangular field \[=(3{{a}^{2}}+5ab+2{{b}^{2}})sq.unit\] One side \[=(a+b)\] unit To find the other side we factorize \[3{{a}^{2}}+5ab+2{{b}^{2}}\] \[\therefore 3{{a}^{2}}+5ab+2{{b}^{2}}=3{{a}^{2}}+3ab+2ab+2{{b}^{2}}\] \[=3a(a+b)+2b(a+b)\] \[=(a+b)(3a+2b)\] \[\therefore \] Other side of rectangle \[=(3a+2b)\] unit So, length of fence around the field \[=2[(a+b)+(3a+2b)]\] \[=(8a+6b)\]units
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