A) 160
B) 100
C) 120
D) 140
Correct Answer: A
Solution :
(a): \[{{\left( 3a+4b \right)}^{2}}={{16}^{2}}\] \[\Rightarrow 9{{a}^{2}}+16{{b}^{2}}+24ab=256\] But, ab = 4 \[\Rightarrow 9{{a}^{2}}+16{{b}^{2}}+24ab=256\] \[\Rightarrow 9{{a}^{2}}+16{{b}^{2}}=160.\]You need to login to perform this action.
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