A) \[\frac{11n-3}{2mn}\]
B) \[\frac{13n-3}{2{{m}^{2}}n}\]
C) \[\frac{11n-3}{2{{m}^{2}}n}\]
D) \[\frac{13n-3}{2mn}\]
Correct Answer: D
Solution :
(d): \[\frac{6}{m}-\frac{(3-n)}{2mn}\] \[=\frac{12n-3+n}{2mn}=\frac{13n-3}{2mn}\]
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