A) 16
B) 18
C) 14
D) 12
Correct Answer: C
Solution :
(c): \[x+\frac{1}{x}=4\] \[\Rightarrow {{\left( x+\frac{1}{x} \right)}^{2}}=16={{x}^{2}}+\frac{1}{{{x}^{2}}}+2=16\] \[\Rightarrow {{x}^{2}}+\frac{1}{{{x}^{2}}}=14.\]You need to login to perform this action.
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