A) 10
B) 15
C) \[\sqrt{15}\]
D) 12
Correct Answer: B
Solution :
(b): \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=125\] ......1 \[ab+bc+ca=50\] ......2 From \[1+2\times 2\] \[\Rightarrow {{a}^{2}}+{{b}^{2}}+{{c}^{2}}+2\left\{ ab+bc+ca \right\}=125+2\times 50\]\[\Rightarrow {{\left( a+b+c \right)}^{2}}=225\] \[\Rightarrow a+b+c=15\]You need to login to perform this action.
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