A) \[(1+r)(b+r)-1b\]
B) \[1b-(1-r)(b-r)\]
C) \[(1+b-r)r\]
D) \[1b-(1-2r)(b-2r)\]
Correct Answer: C
Solution :
Area of the path along length \[=l\times r\] Area of the path along breadth \[=b\times r\] The common area of the paths \[={{b}^{2}}\] \[\therefore \]Total area of the path \[=lr+lr-{{r}^{2}}=(l+b-r)r\]You need to login to perform this action.
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