| \[\frac{9}{10}(30+5t)+\frac{5}{6}(18t-12)\] |
A) \[-17+\frac{39}{2}t\]
B) \[17t-\frac{39}{2}\]
C) \[\left( 17+\frac{39}{2}t \right)\]
D) \[17t+\frac{39}{2}\]
Correct Answer: C
Solution :
\[\frac{9}{10}(30+5t)+\frac{5}{6}\,(18t-12)\]\[=\left( 17+\frac{39}{2}t \right)\]
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