A) \[C{{l}_{2}}\]
B) \[{{H}_{2}}\]
C) \[{{O}_{2}}\]
D) \[{{H}_{2}}O\]
Correct Answer: A
Solution :
\[2NaCl+2{{H}_{2}}O\to 2NaOH+\underset{\text{Anode}}{\mathop{C{{l}_{2}}}}\,+\underset{\text{Cathode}}{\mathop{{{H}_{2}}}}\,\]You need to login to perform this action.
You will be redirected in
3 sec