A) \[C{{H}_{3}}I\]
B) \[{{C}_{2}}{{H}_{5}}I\]
C) \[C{{H}_{3}}OH\]
D) \[{{C}_{2}}{{H}_{5}}OH\]
Correct Answer: A
Solution :
\[C{{H}_{3}}I+2H\xrightarrow{Zn/HCl}C{{H}_{4}}+HI\] \[C{{H}_{3}}I+2Na+IC{{H}_{3}}\underset{\text{Ether}}{\mathop{\xrightarrow{\text{Dry}}}}\,C{{H}_{3}}-C{{H}_{3}}+2NaI\]
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