A) Markowikoff's
B) Bayer
C) Saytzeff
D) Wurtz
Correct Answer: C
Solution :
\[\underset{\text{2}-\text{Bromo}\,\text{butane}\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-\underset{\underset{Br\,}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\to C{{H}_{3}}-CH=CH-C{{H}_{3}}+HBr\]You need to login to perform this action.
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