A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-CH=C{{H}_{2}}\xrightarrow{HBr}\]\[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{2}-\text{Bromo}\,\text{butane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\underset{Br\,}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{3}}}}\,\]You need to login to perform this action.
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