A) Propanal
B) Propanol
C) Propyl hydrogen sulphate
D) Propanone
Correct Answer: D
Solution :
\[C{{H}_{3}}-C\equiv CH+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}}}\] \[\underset{\text{Prop}-\text{1}-\text{ene}\,\text{2}\,-\text{ol}}{\mathop{\left[ C{{H}_{3}}-\overset{\overset{OH}{\mathop{|\,\,\,}}\,}{\mathop{C\,=}}\,C{{H}_{2}} \right]}}\,\]You need to login to perform this action.
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