A) \[\begin{matrix} CI\,\,\, \\ C{{H}_{3}} \\ \end{matrix}>C=C<\begin{matrix} Cl\,\,\,\,\,\,\,\,\,\,\, \\ C{{H}_{2}}C{{H}_{3}} \\ \end{matrix}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-\underset{\,\,Cl}{\overset{\,Cl}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{2}}C{{H}_{3}}\]
C) \[\begin{matrix} Cl\,\,\, \\ C{{H}_{3}} \\ \end{matrix}>C=C<\begin{matrix} C{{H}_{2}}C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\, \\ Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\ \end{matrix}\]
D) \[C{{H}_{3}}-\underset{\,Cl}{\overset{\,Cl}{\mathop{\underset{|}{\overset{|\,}{\mathop{C}}}\,}}}\,-\underset{\,Cl}{\overset{\,Cl}{\mathop{\underset{|\,}{\overset{\,|\,\,}{\mathop{C\,}}}\,}}}\,-C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: D
Solution :
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