A) 10
B) 13
C) 14
D) 17
Correct Answer: D
Solution :
\[\text{3}={{\text{2}}^{\text{2}}}-\text{1},\]\[\text{1}0={{\text{3}}^{\text{2}}}+\text{1}\] \[\text{8}={{\text{3}}^{\text{2}}}-\text{1},\] \[\text{17}={{\text{4}}^{\text{2}}}+\text{1}\]You need to login to perform this action.
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