A) P, Y
B) P, Z
C) Y, Z
D) Z, A
Correct Answer: A
Solution :
The given series may be divided into groups of five letters each: \[AJKTU/BILSV/CHMRW/DGNQX/EFO??\] The first, second, third, fourth & fifth letters of consecutive groups form sequences (A, B, C, D, E), (J, I, H, G, F), (K, L, M, N, O), (T, S, R, Q, ?) and (U, V, W, X, ?) respectively. Thus, the missing letters are P and Y.You need to login to perform this action.
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