A) \[\tan \theta =\frac{2({{h}^{2}}-ab)}{(a+b)}\]
B) \[\tan \theta =\frac{2\sqrt{{{h}^{2}}-ab}}{(a+b)}\]
C) \[\tan \theta =\frac{2({{h}^{2}}-ab)}{\sqrt{a+b}}\]
D) \[\tan \theta =\frac{2\sqrt{{{h}^{2}}+ab}}{(a+b)}\]
Correct Answer: B
Solution :
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