A) 2
B) 0
C) 3
D) 1
Correct Answer: A
Solution :
Given that \[\theta ={{\tan }^{-1}}\left( \frac{1}{3} \right)\] Þ \[\tan \theta =\frac{1}{3}\] Now, since \[\tan \theta =\frac{2\sqrt{{{h}^{2}}-ab}}{a+b}\]Þ \[\frac{1}{3}\,=\frac{2\sqrt{{{\left( \frac{-3}{2} \right)}^{2}}-\lambda }}{\lambda +1}\] Þ \[{{(\lambda +1)}^{2}}=9(9-4\lambda )\] Þ \[{{\lambda }^{2}}+38\lambda -80=0\] Þ \[\lambda =\frac{-38\pm \sqrt{{{(38)}^{2}}+320}}{2}\]Þ \[\lambda =\frac{-38\pm 42}{2}\]Þ \[\lambda =2\].You need to login to perform this action.
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