A) \[{{30}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer: B
Solution :
\[\theta ={{\tan }^{-1}}\left( \frac{2-\sqrt{3}-2-\sqrt{3}}{1+4-3} \right)={{\tan }^{-1}}(-\sqrt{3})={{120}^{o}}\] Considering smaller angle\[{\theta }'={{60}^{o}}\].You need to login to perform this action.
You will be redirected in
3 sec