A) \[\frac{3}{2}\,sec\]
B) \[\frac{2}{3}sec\]
C) \[\frac{1}{2}sec\]
D) Never
Correct Answer: A
Solution :
\[\frac{ds}{dt}=6{{t}^{2}}-18t+12\] Again\[\frac{{{d}^{2}}s}{d{{t}^{2}}}=12t-18\]= acceleration If acceleration becomes zero, then \[0=12t-18\] Þ \[t=\frac{3}{2}\sec .\]Hence acceleration will be zero after \[\frac{3}{2}\]sec.
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