A) \[\frac{10}{3}\sec \]
B) \[\frac{5}{3}\sec \]
C) \[\frac{20}{3}\sec \]
D) \[\frac{5}{6}\sec \]
Correct Answer: A
Solution :
\[\frac{ds}{dt}=10-6t=v\] But \[v=0\] (at maximum height), \[\therefore t=\frac{10}{6}\] Therefore, the stone will return in \[2\times \frac{10}{6}=\frac{10}{3}\sec .\]You need to login to perform this action.
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