A) h/3
B) 2h
C) h
D) 0
Correct Answer: D
Solution :
The time taken by first stone to secure maximum height =\[t=\frac{u}{g}=\frac{19.6}{9.8}=2sec\]. The time taken by second stone to secure maximum height is, \[t=\frac{9.8}{9.8}=\]1sec. Therefore, in 2 sec, second stone will come back to the ground. Hence height \[s=a{{t}^{2}}+bt+6\].You need to login to perform this action.
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