A) 3
B) 9
C) 15
D) 27
Correct Answer: B
Solution :
Motion of a particle \[s=15t-2{{t}^{2}}\] Therefore, velocity \[\frac{ds}{dt}=15-4t\] Þ \[{{\left( \frac{ds}{dt} \right)}_{t=0}}=15\]and \[{{\left( \frac{ds}{dt} \right)}_{t=3}}=3\] Therefore, average \[=\frac{15+3}{2}=9\].You need to login to perform this action.
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