JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Application in Mechanics and Rate Measurer

  • question_answer
    If the volume of a spherical balloon is increasing at the rate of 900cm3per sec, then the rate of change of radius of balloon at instant when radius is 15cm [in cm/sec]  [RPET 1996]

    A)            \[\frac{22}{7}\]

    B)            22

    C)            \[\frac{7}{22}\]

    D)            None of these

    Correct Answer: C

    Solution :

               \[V=\frac{4}{3}\pi {{r}^{3}}\]                    Differentiate with respect to t,                    \[\frac{dV}{dt}=\frac{4}{3}\pi 3{{r}^{2}}.\frac{dr}{dt}\]Þ\[\frac{dr}{dt}=\frac{1}{4\pi {{r}^{2}}}.\frac{dV}{dt}\]                    \[\frac{dr}{dt}=\frac{1}{4\times \pi \times 15\times 15}\times 900\]\[\Rightarrow \]\[\frac{dr}{dt}=\frac{1}{\pi }=\frac{7}{22}\].


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