A) 3
B) ? 2
C) ? 3
D) 2
Correct Answer: C
Solution :
Given \[s={{t}^{3}}-3{{t}^{2}}\] \ \[v=\frac{ds}{dt}=3{{t}^{2}}-6t\], \[a=\frac{{{d}^{2}}s}{d{{t}^{2}}}=6t-6\] Acceleration is zero, if \[6t-6=0\]Þ \[t=1\] \ Required velocity of particle at \[t=1\] is \[v=3{{(1)}^{2}}-6(1)\] \[\Rightarrow \,v=-3\].You need to login to perform this action.
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