A) Zero
B) Uniform
C) Non-uniform
D) Indeterminate
Correct Answer: B
Solution :
\[{{v}^{2}}=a+bx\] Þ \[2v\frac{dv}{dt}=b\frac{dx}{dt}\]Þ\[2v\frac{dv}{dt}=bv\] Þ \[\frac{dv}{dt}=\frac{b}{2}\] Hence acceleration is constant or uniform.You need to login to perform this action.
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