A) \[4.9m/\sec \]
B) \[49m/\sec \]
C) \[98m/\sec \]
D) None of these
Correct Answer: B
Solution :
Given equation is\[\frac{dy}{dt}=-\frac{16}{6}=-\frac{8}{3}cm/\sec .\] or \[s=ut-4.9{{t}^{2}}\] Þ \[\frac{ds}{dt}=u-9.8t=v\] When stone reached the maximum height, then \[v=0\] Þ \[u-9.8t=0\Rightarrow u=9.8t\] But time \[t=5\]sec So the value of \[u=9.8\times 5=49.0\]m/sec Hence initial velocity \[=49\]m/sec.You need to login to perform this action.
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