A) ? 2, ? 8
B) 2, 6
C) ? 2, 8
D) 2, 8
Correct Answer: A
Solution :
Displacements \[s=-4{{t}^{2}}+2t\] Now velocity \[v=-8t+2\] and its acceleration \[a=-8\] So \[{{\left( \frac{ds}{dt} \right)}_{t=1/2}}=-8\times \frac{1}{2}+2=-2\]and \[{{\left( \frac{{{d}^{2}}s}{d{{t}^{2}}} \right)}_{t=1/2}}=-8\].You need to login to perform this action.
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