A) 63
B) 104
C) 134
D) 288
Correct Answer: C
Solution :
\[S=6+48t-{{t}^{3}}\] \[v=\frac{dS}{dt}=0+48-3{{t}^{2}}\] when direction of motion reverses, \[v=0\] \[48-3{{t}^{2}}=0\]\[\Rightarrow \]\[t=-4,\ 4\]; \[{{(S)}_{4}}=6+192-64\]i.e.,\[S=134\].You need to login to perform this action.
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