A) 16 cm/sec
B) 20 cm/sec
C) 8 cm/sec
D) 12 cm/sec
Correct Answer: C
Solution :
Time of encounter \[10+6t=3+{{t}^{2}}\] Þ \[{{t}^{2}}-6t-7=0\], \[t=7\]sec. At \[t=7\sec \]., \[{{v}_{1}}=\frac{d}{dt}(10+6t)=6\,\]cm/sec At\[t=7\sec .\] \[{{v}_{2}}=\frac{d}{dt}(3+{{t}^{2}})=2t=2\times 7=14\]cm/sec \Resultant velocity = \[{{v}_{2}}-{{v}_{1}}=14-6=8\,\]cm/secYou need to login to perform this action.
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