A) \[{{x}^{2}}+{{y}^{2}}=1\]
B) \[{{x}^{2}}-{{y}^{2}}=1\]
C) \[2{{x}^{2}}+{{y}^{2}}=2\]
D) None of these
Correct Answer: B
Solution :
We have \[\frac{dx}{x}=\frac{y\,dy}{1+{{y}^{2}}}\] Integrating, we get \[\log |x|=\frac{1}{2}\log (1+{{y}^{2}})+\log c\] or \[|x|=c\sqrt{(1+{{y}^{2}})}\] But it passes through (1, 0), so we get \[c=1\] \[\therefore \]Solution is \[{{x}^{2}}={{y}^{2}}+1\]or\[{{x}^{2}}-{{y}^{2}}=1\].
You need to login to perform this action.
You will be redirected in
3 sec
