A) \[y={{x}^{2}}+x+1\]
B) \[xy={{x}^{2}}+x+1\]
C) \[xy=x+1\]
D) None of these
Correct Answer: B
Solution :
We have \[\frac{dy}{dx}=1-\frac{1}{{{x}^{2}}}\] Þ \[y=x+\frac{1}{x}+c\] This passes through \[\left( 2,\frac{7}{2} \right)\], \ \[\frac{7}{2}=2+\frac{1}{2}+c\] Þ \[c=1\] Thus the equation of the curve is \[y=x+\frac{1}{x}+1\] or\[xy={{x}^{2}}+x+1\].You need to login to perform this action.
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