A) \[x=\frac{1}{4}\]
B) \[x=\frac{3}{4}\]
C) \[x=\frac{1}{2}\]
D) x = 1
Correct Answer: C
Solution :
Given \[\frac{dx}{dt}={{\cos }^{2}}\pi x\]. Differentiate w.r.t. t, \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=-2\pi \sin 2\pi x=-ve\] \[\because \] \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=0\] Þ \[-2\pi \sin 2\pi x=0\] Þ \[\sin 2\pi x=\sin \pi \] Þ \[2\pi x=\pi \] Þ \[x=1/2\].You need to login to perform this action.
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