A) \[(y-1)(x+1)+2x=0\]
B) \[2x(y-1)+x+1=0\]
C) \[x(y-1)(x+1)+2=0\]
D) None of these
Correct Answer: A
Solution :
Slope \[=\frac{dy}{dx}\] Þ \[\frac{dy}{dx}=\frac{y-1}{{{x}^{2}}+x}\]Þ\[\frac{dy}{y-1}=\frac{dx}{{{x}^{2}}+x}\] Þ\[\int_{{}}^{{}}{\frac{1}{y-1}}dy=\int_{{}}^{{}}{\left( \frac{1}{x}-\frac{1}{x+1} \right)\text{ }}dx+c\]Þ\[\frac{(y-1)(x+1)}{x}=k\] Putting \[x=1\],\[y=0\], we get \[k=-2\] Hence the equation is \[(y-1)(x+1)+2x=0\].You need to login to perform this action.
You will be redirected in
3 sec