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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Application of EMI (Motor, Dynamo, Transformer)

  • question_answer
    The number of turns in the coil of an ac­ generator is 5000 and the area of the coil is \[0.25\,{{m}^{2}}\]. The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2\[W/{{m}^{2}}\]. The peak value of the emf generated is nearly      [AMU 1995]

    A)            786 kV                                     

    B)            440 kV

    C)            220 kV                                     

    D)            157.1 Kv

    Correct Answer: D

    Solution :

                       \[{{e}_{0}}=\omega NBA=(2\pi \nu )\ NBA\]            \[=2\times 3.14\times 1000\times 5000\times 0.2\times 0.25\]= 157 kV


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