JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Application of EMI (Motor, Dynamo, Transformer)

  • question_answer
    The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an ac supply of 120 V and the current flowing in it is 10 A. The voltage and the current in the secondary are [MP PMT 1991; DPMT 2004]

    A)            240 V, 5 A                              

    B)             240 V, 10 A

    C)            60 V, 20 A                              

    D)             120 V, 20 A

    Correct Answer: A

    Solution :

                       \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{V}_{s}}}{{{V}_{p}}}\Rightarrow \frac{200}{100}=\frac{{{V}_{s}}}{120}\Rightarrow {{V}_{s}}=240\ V\]            also \[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{i}_{p}}}{{{i}_{s}}}\Rightarrow \frac{240}{120}=\frac{10}{{{i}_{s}}}\Rightarrow {{i}_{s}}=5\ A\]


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