A) 20 A, 220 V
B) 0.4 A, 22000 V
C) 40 A, 220 V
D) 40 A, 22000 V
Correct Answer: C
Solution :
\[\frac{{{N}_{p}}}{{{N}_{s}}}=\frac{{{V}_{p}}}{{{V}_{s}}}=\frac{{{i}_{s}}}{{{i}_{p}}}\]. The transformer is step-down type, so primary coil will have more turns. Hence \[\frac{5000}{500}=\frac{2200}{{{V}_{s}}}=\frac{{{i}_{s}}}{4}\Rightarrow {{V}_{s}}=220\ V,\ {{i}_{s}}=40\ amp\]
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