A) \[3\Omega \]
B) \[6\Omega \]
C) \[15\Omega \]
D) \[30\Omega \]
Correct Answer: A
Solution :
Efficiency \[\eta =50%\ \]So \[e=E/2\] and \[i=\frac{E-e}{R}\Rightarrow i=\frac{E-E/2}{R}=\frac{E}{2R}\] \[\Rightarrow R=\frac{E}{2i}=\frac{60}{2\times 10}=3\Omega \]You need to login to perform this action.
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