JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Application of EMI (Motor, Dynamo, Transformer)

  • question_answer
    In a transformer, the number of turns in primary and secondary are 500 and 2000 respectively. If current in primary is 48 A, the current in the secondary is  [Orissa PMT 2004]

    A)            12 A                                         

    B)            24 A

    C)            48 A                                         

    D)            144 A

    Correct Answer: A

    Solution :

               \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{i}_{p}}}{{{i}_{s}}}\Rightarrow \frac{2000}{500}=\frac{48}{{{i}_{s}}}\Rightarrow {{i}_{s}}=12A\]


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