A) 40 A, 16 A
B) 16 A, 40 A
C) 20 A, 40 A
D) 40 A, 20 A
Correct Answer: A
Solution :
\[\eta =\frac{\text{output}\,\text{power}}{\text{input}\,\text{power}}=\frac{{{E}_{s}}{{I}_{s}}}{{{E}_{p}}{{I}_{p}}}\] Þ \[\frac{80}{100}=\frac{200\times {{I}_{s}}}{4\times {{10}^{3}}}\] Þ \[{{I}_{S}}=\frac{80}{100}\times \frac{4\times 1000}{200}=16A\] Also, \[{{E}_{p}}{{I}_{p}}=4KW\]Þ\[{{I}_{p}}=\frac{4\times {{10}^{3}}}{100}=40A\]
You need to login to perform this action.
You will be redirected in
3 sec
