JEE Main & Advanced Mathematics Vector Algebra Question Bank Application of vectors in three dimensional geometry

  • question_answer
    The length of the perpendicular from the origin to the plane passing through the point a and containing the line \[\mathbf{r}=\mathbf{b}+\lambda \mathbf{c}\] is

    A)            \[\frac{[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]}{|\mathbf{a}\times \mathbf{b}+\mathbf{b}\times \mathbf{c}+\mathbf{c}\times \mathbf{a}|}\]

    B)            \[\frac{\,[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]}{|\mathbf{a}\times \mathbf{b}+\mathbf{b}\times \mathbf{c}|}\]

    C)          \[\frac{[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]}{|\mathbf{b}\times \mathbf{c}+\mathbf{c}\times \mathbf{a}|}\]

    D)            \[\frac{[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]}{|\mathbf{c}\times \mathbf{a}+\mathbf{a}\times \mathbf{b}|}\]

    Correct Answer: C

    Solution :

               The given plane passes through \[\mathbf{a}\] and is parallel to the vectors \[\mathbf{b}-\mathbf{a}\] and \[\mathbf{c}\]. So it is normal to \[(\mathbf{b}-\mathbf{a})\times \mathbf{c}\]. Hence, its equation is \[(\mathbf{r}-\mathbf{a}).((\mathbf{b}-\mathbf{a})\times \mathbf{c})=0\]                    or  \[\mathbf{r}.(\mathbf{b}\times \mathbf{c}+\mathbf{c}\times \mathbf{a})=[\mathbf{a}\,\mathbf{b}\,\mathbf{c}\,]\]                    The length of the perpendicular from the origin to this plane is \[\frac{[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]}{|\mathbf{b}\times \mathbf{c}+\mathbf{c}\times \mathbf{a}|}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner