A) \[{{\cos }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]
B) \[{{\cos }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]
C) \[{{\sin }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]
D) \[{{\sin }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]
Correct Answer: D
Solution :
Use the formula, \[\sin \theta =\frac{\mathbf{n}.\mathbf{b}}{|\mathbf{n}||\mathbf{b}|}\].You need to login to perform this action.
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