JEE Main & Advanced Mathematics Vector Algebra Question Bank Application of vectors in three dimensional geometry

  • question_answer
    Angle between the line \[\mathbf{r}=(2\mathbf{i}-\mathbf{j}+\mathbf{k})+\lambda (-\mathbf{i}+\mathbf{j}+\mathbf{k})\] and the plane \[\mathbf{r}.(3\mathbf{i}+2\mathbf{j}-\mathbf{k})=4\] is

    A)            \[{{\cos }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]

    B)            \[{{\cos }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]

    C)            \[{{\sin }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]

    D)            \[{{\sin }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]

    Correct Answer: D

    Solution :

               Use the formula, \[\sin \theta =\frac{\mathbf{n}.\mathbf{b}}{|\mathbf{n}||\mathbf{b}|}\].


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