A) Circle
B) Plane
C) Sphere of radius 4
D) Sphere of radius 3
E) None of these
Correct Answer: C
Solution :
Since the equation \[|\mathbf{r}{{|}^{2}}-2(\mathbf{r}.\mathbf{a})+\lambda =0\] represents a sphere of radius \[\sqrt{|\mathbf{a}{{|}^{2}}-\lambda }\], therefore \[|\mathbf{r}{{|}^{2}}-\mathbf{r}.(2\mathbf{i}+4\mathbf{j}-2\mathbf{k})-10=0\] represents a sphere of radius \[=\sqrt{|\mathbf{i}+2\mathbf{j}-\mathbf{k}{{|}^{2}}+10}=\sqrt{6+10}=4\].
You need to login to perform this action.
You will be redirected in
3 sec
