A) \[\mathbf{r}.(2\mathbf{i}+3\mathbf{j}+6\mathbf{k})=28\]
B) \[\mathbf{r}.(2\mathbf{i}+3\mathbf{j}+6\mathbf{k})=32\]
C) \[\mathbf{r}.(2\mathbf{i}+3\mathbf{j}+6\mathbf{k})+28=0\]
D) None of these
Correct Answer: C
Solution :
The required plane is \[\{\mathbf{r}-(\mathbf{i}-2\mathbf{j}-4\mathbf{k})\}.\overrightarrow{PQ}=0\].You need to login to perform this action.
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