A) \[16\log 2-13\]
B) \[16\log 2-3\]
C) \[16\log 2+3\]
D) None of these
Correct Answer: C
Solution :
Given curve is \[y(x-2)=3x+10\Rightarrow y=\frac{3x+10}{x-2}\] Required area is \[\int_{3}^{4}{\,\,y\,dx=\int_{3}^{4}{\frac{3x+10}{x-2}\,\,dx}}\] =\[[3x+16\log (x-2)]_{3}^{4}=3+16\log 2\] sq. unit.You need to login to perform this action.
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